crwdns2933423:0crwdne2933423:0
crwdns2918538:0crwdne2918538:0

crwdns2934243:0crwdne2934243:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,
What voltage supply being used?
Power (watts) = voltage (Volts) x current (Amps).
-You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V e.g. 3000W ÷ 230V = 13.04A or 3000 ÷ 120V = 25A
+You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V e.g. 3000W ÷ 230V = 13.04A or 3000W ÷ 120V = 25A
Also the type of cable insulation is important as well.
Here's a [link|https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open

crwdns2934245:0crwdne2934245:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,
What voltage supply being used?
Power (watts) = voltage (Volts) x current (Amps).
-You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V e.g. 3000W ÷ 230V = 13.04A
+You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V e.g. 3000W ÷ 230V = 13.04A or 3000 ÷ 120V = 25A
Also the type of cable insulation is important as well.
Here's a [link|https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open

crwdns2934245:0crwdne2934245:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,
What voltage supply being used?
Power (watts) = voltage (Volts) x current (Amps).
-You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V
+You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V e.g. 3000W ÷ 230V = 13.04A
Also the type of cable insulation is important as well.
Here's a [link|https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open

crwdns2934245:0crwdne2934245:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,
What voltage supply being used?
Power (watts) = voltage (Volts) x current (Amps).
-You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size.
+You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size i.e. A=P÷V
Also the type of cable insulation is important as well.
Here's a [link|https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open

crwdns2934245:0crwdne2934245:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,
What voltage supply being used?
Power (watts) = voltage (Volts) x current (Amps).
-You have supplied the power but not the voltage, but it is the current value (Amperes) that has to be known when determining the cable size.
+You have supplied the power value (kW) and not the supply voltage value, but it is the current value (Amperes) that has to be known when determining the cable size.
Also the type of cable insulation is important as well.
-Here's a [https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.
+Here's a [link|https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open

crwdns2934241:0crwdne2934241:0 jayeff

crwdns2934249:0crwdne2934249:0:

Hi @adarshmohanty,

What voltage supply being used?

Power (watts) = voltage (Volts) x current (Amps).

You have supplied the power but not the voltage, but it is the current value (Amperes) that has to be known when determining the cable size.

Also the type of cable insulation is important as well.

Here's a [https://www.electricalvolt.com/2023/06/current-carrying-capacity-of-aluminium-cable/|link] that may help.

crwdns2915684:0crwdne2915684:0:

open